Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In a Δ ABC, if a, b, c and A are given, then there are two Δ ’s with third sides c 1 and c 2 , then (c 1 – c 2 ) is -
A
Ab sin A
B
C
D
2ab sin A
Text Solution
Verified by ExpertsThe correct answer is:
C
a 2 = b 2 + c 2 – 2bc cos A
⇒ c 2 – 2bc cos A + (b 2 – a 2 ) = 0
Clearly c 1 and c 2 are roots of equation
c 1 + c 2 = 2b cos A, c 1 c 2 = b 2 – a 2 ∴ c 1 – c 2 = 
= 
= 
= 
.
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